Question

In the following figure the current through $4\Omega$ resistor is

• A. 1.4 A
• B. 0.4 A
• C. 1.0 A
• D. 0.7 A

Answer 1

Answer: (C)

1.0 A

Since $\frac{P}{Q}=\frac{R}{S}\Rightarrow$$\frac{20}{4}=\frac{50}{10}$, It is an example of balanced wheat-stone bridge.

So, No current will flow through $16\Omega$ resistance.

As we know that current divide in inverse ratio, current through $4\Omega$ resistance $=1.4\times \frac{50+10}{(20+4)+(50+10)}=1.4\times \frac{5}{7}=1A$

Therefore, C is correct option.