Question

In the following figure, what is the midpoint of $\overline{UV}$?

• A. $(-1,\frac{1}{2})$
• B. $(-1,\frac{3}{2})$
• C. $(-1,-\frac{1}{2})$
• D. $(-2,\frac{1}{2})$
• E. $(-2,-\frac{3}{2})$

Answer 1

Answer: (A)

$(-1,\frac{1}{2})$

Given are the two points of the line $VU$
Let point on $V$ be$\left(x_1{y}_1\right)$ $=(1,8)$
Let point on $U$ be $\left(x_2{y}_2\right)$ $=(-3,-7)$
We know the midpoint formula is
$\left(x_m{y}_m\right)=[\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}]$
Putting the values of in the formula, we get
$\left(x_m{y}_m\right)=[\frac{1+(-3)}{2},\frac{8+(-7)}{2}]$
$\left(x_m{y}_m\right)=[\frac{-2}{2},\frac{1}{2}]$
$\left(x_m{y}_m\right)=[-1,\frac{1}{2}]$