Question

In the following figure, XY is parallel to BC AX =9 cm, XB =4.5 cm and BC =18 cm.

Then, $\frac{AY}{YC}$ = ___

Answer 1

In the given figure,

XY ||BC

AX =9 cm, XB =4.5 cm, BC =18 cm

In $\Delta ABC,XY||BC$

$\therefore \frac{AX}{AB}=\frac{AX}{AC}=\frac{XY}{BC}$

$\Rightarrow \frac{AX}{AB}=\frac{9}{9+4.5}=\frac{9}{13.5}=\frac{2}{3}$

$\frac{AY}{YC}=\frac{9}{4.5}=\frac{2}{1}=2$