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Question

In the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation :
5x(5x)=12(3x);43y=4+y3
solution is (1,45)
If true then enter 1 and if false then enter 0

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Solution

First equation:
5x(5x)= 12(3x)


5x5+x= 12(3x)


6x5= 12(3x)

12x10=3x

13x=13

x=1


Second equation:
43y=4+y3


129y=4+y


y=45
Hence, required point =(x,y)=(1, 45 )


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