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Question

In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface (Tst)
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth (Tma)
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/k (Tsp)
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field (Tis)

A
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B
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C
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D
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Solution

The correct option is C
(i) Tst=2π(R+h)3GM=2πRg [As h<<R and GM=R2](ii) Tma=2πRg(iii) Tsp=2π1g(1l+1R)=2πR2g [As l=R](iv) Tis=2πRg [As l=]

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