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Byju's Answer
Standard IX
Mathematics
Ungrouped Frequency Table
In the follow...
Question
In the following frequency distribution of
165
observations, the mode is
34.5
. Find the missing frequencies
a
and
b
.
Class
5
−
14
14
−
23
23
−
32
32
−
41
41
−
50
50
−
59
59
−
68
Frequency
5
11
a
53
b
16
10
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Solution
⇒
Here, modal class
=
32
−
41
⇒
l
=
32
,
f
0
=
a
,
f
1
=
53
,
f
2
=
b
and
h
=
9
⇒
M
o
d
e
=
l
+
f
1
−
f
0
2
f
1
−
f
0
−
f
2
×
h
⇒
34.5
=
32
+
53
−
a
2
×
53
−
a
−
b
×
9
⇒
2.5
9
=
53
−
a
106
−
a
−
b
⇒
265
−
2.5
a
−
2.5
b
=
477
−
9
a
⇒
7.5
a
−
2.5
b
=
212
⇒
75
a
−
25
b
=
2120
∴
13
a
−
5
b
=
424
------ ( 1 )
As total observation are
165
⇒
So,
5
+
11
+
a
+
53
+
b
+
16
+
10
=
165
⇒
95
+
a
+
b
=
165
∴
a
+
b
=
70
-------- ( 2 )
∴
b
=
70
−
a
Substitute
b
=
70
−
a
in equation ( 1 )
⇒
13
a
−
5
(
70
−
a
)
=
424
⇒
13
a
−
350
+
5
a
=
424
⇒
18
a
=
424
+
350
⇒
18
a
=
774
∴
a
=
43
⇒
b
=
70
−
43
=
27
∴
Frequency
a
=
43
and
b
=
27
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1
Similar questions
Q.
Given below are the marks obtained by
30
students in an examination:
08
17
33
41
47
23
20
34
09
18
42
14
30
19
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11
36
48
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24
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02
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01
Taking class intervals
1
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−
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.
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make a frequency table for the above distribution.
Q.
In an examination taken by
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Marks
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−
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−
21
21
−
30
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40
41
−
50
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−
60
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Find the mode scores?
Q.
The mean of the following frequency distribution is
16
, find the missing frequency
Class
0-4
4-8
8-12
12-16
16-20
20-24
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17
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3
Q.
Draw a cumulative frequency curve for the following frequency distribution.
Class Interval
0
−9
10
−19
20
−29
30
−39
40
−49
50
−59
60
−69
Frequency
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15
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