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Question

In the following functions defined from [1,1] to [1,1], then functions which are not bijective are

A
sin(sin1x)
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B
2πsin1(sinx)
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C
(sgnx) lnex
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D
x3sgnx
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Solution

The correct options are
B 2πsin1(sinx)
C (sgnx) lnex
D x3sgnx
sinsin1x=x hence it is bijective.

2πsin1sinx= 2xπ. Hence it is one one but not onto, hence not bijective

sgn(x).x=|x|x.x=|x|,x0
Hence it is not one one or onto, hence not bijective

x3sgnx=x3|x|x=x2|x|=|x|3,x0. Hence function is not one one or onto, hence not bijective.

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