In the following gaseous phase first order reaction A(g)→2B(g)+C(g) initial pressure was found to be 400 mm of Hg and it changed to 1000 mm of Hg after 204 min. Then:
A
half life for A is 10 min
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B
rate constant is 0.0693 min−1
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C
partial pressure of C at 30 min is 350 mm of Hg
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D
total pressure after 30 min is 1100 mm of Hg
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Solution
The correct options are A half life for A is 10 min B rate constant is 0.0693 min−1 C partial pressure of C at 30 min is 350 mm of Hg D total pressure after 30 min is 1100 mm of Hg A(g) → 2B(g) + C(g) t = 0 400 0 0 t = 20 min 400 - p 2p p Given 400−p+2p+p=1000 400+2p=1000 p=300mm k=120ln400400−300=120ln4 k=fracln210min−1 T1/2=10min ValueofK=0.0693min−1 After 30 min Partial Pressure of A is 50 mm After 30 min Partial Pressure of B is 700 mm After 30 min Partial Pressure of C is 350 mm After 30 min total pressure become 1100 mm So all of the above are correct.