In the following mixed Claisen ester condensation reaction, the expected products are
$C H_{3} C O O C_{2} H_{5} + C H_{3} C H_{2} C O O C_{2} H_{5} C_{2} H_{5} O N a ⟶ C_{2} H_{5} O H$

H_{3} C - O | | C - C H | C H_{3} - C O O C_{2} H_{5}

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C H_{3} C H_{2} - O | | C - C H_{2} C H_{2} - C O O C_{2} H_{5}

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H_{3} C - O | | C - C H_{2} C H_{2} - C O O C_{2} H_{5}

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C H_{3} C H_{2} - O | | C - C H | C H_{3} - C O O C_{2} H_{5}

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Solution

The correct option is A $C H_{3} C H_{2} - O | | C - C H_{2} C H_{2} - C O O C_{2} H_{5}$
A similar reaction mechanism is shown above. When enolizable ketones are subject to the conditions they undergo condensation reaction with esters. This condensation reaction is known as a crossed or mixed Claisen condensation.
The product formed is given by option B.

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C_{6} H_{5} - C H O + B r - C H_{2} - C O O C_{2} H_{5} (i) Z n - -------------- \to (i i) H O H / N H_{4} C l (i i i) Δ

C_{6} H_{5} - C H = C H - C O O C_{2} H_{5}

{C H}_{3} - C H = {C H}_{2} + H B r ⟶ {C H}_{3} C H_{2} {C H}_{2} B r (A) + {C H}_{3} - C H | B r - C H_{3} (B)

H_{3} C - O | | C - C H_{3}

H_{3} C - O | | C - C H_{2} - O | | C - C H_{3}

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H_{3} C - O | | C - O H

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C H_{3} C O O C_{2} H_{5} + C_{6} H_{5} - C H_{2} - C O O C_{2} H_{5} C_{2} H_{5} O N a - ----- \to C_{2} H_{5} O H

C H_{3} C H_{2} - C | | O - C H_{3} N a N O_{2} - --- \to H C l

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