Question

In the following molecule,


Hybridization of carbon a, b and c respectively are:

• A. $s{p}^3,sp,sp$
• B. $s{p}^3,s{p}^2,s{p}^2$
• C. $s{p}^3,sp,s{p}^2$
• D. $s{p}^3,s{p}^2,sp$

Answer 1

The correct option is B $s{p}^3,s{p}^2,s{p}^2$

$\text{Hybridization = Number of lone pairs + Number of sigma bond pairs}$
For:
$a:0+4=4$; So, $s{p}^3$
$b:0+3=3$; So, $s{p}^2$
$c:0+3=3$; So, $s{p}^2$
Hence, option (b) is correct answer.