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Question

In the following molecules:
CH3Br, CH3F, CH3Cl, CH3I I , II , III , IV
The correct order of dipole moment will be:


A

IV > I > III > II

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B

III > II > I > IV

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C

II > III > I > IV

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D

II > IV > III > I

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Solution

The correct option is B

III > II > I > IV


μ=q×d
For CH3F, q is high but d is less and for CH3Cl, q is less but d is high and the net product of q and d is higher for CH3Cl.


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