Question

In the following monobromination reaction, the number of possible chiral product(s) is/are:

Answer 1

1. There is no chiral centre in molecule hence achiral.
2. There is a formation of new chiral centre in a molecule therefore 2¹ = 2 chiral products.
3. There can be two types of substitution here:

Same side substitution as already present chiral centre in a molecule then molecule is achiral because of the POS in it.

Other side substitution as already present chiral centre in a molecule then molecule is chiral.

1. There is a chiral centre in a molecule hence chiral product.
2. There is a chiral centre in a molecule hence chiral product.

Total chiral products = 5