Question

In the following nuclear reaction, identify the particle X.
$n\to p+e^{-}+X$.

Answer 1

The given nuclear reaction : ${}_0^{1}n{\to }_1^{1}p{+}_{-1}^{0}e{+}_Z^{A}X$

Conservation of mass number, $1=1+0+A$

$⟹$ $A=0$

Conservation of atomic number, $0=1+(-1)+Z$

$⟹$ $Z=0$

Thus the particle is ${}_0^{0}X$ which is a gamma photon $\left(\gamma \right)$.