In the following pairs, identify the pair having a different (n+l) value?

4s, 3p

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3d, 4p

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4s, 3d

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4d, 5p

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Solution

The correct option is C 4s, 3d
$(n + l)$ value for $4 s = (4 + 0) = 4, 3 p = (3 + 1) = 4, 3 d = (3 + 2) = 5, 4 p = (4 + 1) = 5, 4 d = (4 + 2) = 6, 5 p = (5 + 1) = 6$
Hence correct option is $4 s, 3 d$ i.e., option C.

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Question 18

Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals.

(a) (i) $n = 3, l = 2, m_{l} = - 2, m_{s} = - \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = - 1, m_{s} = - \frac{1}{2}$

(b) (i) $n = 3, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = - 1, m_{s} = + \frac{1}{2}$

(d) (i) $n = 3, l = 2, m_{l} = + 2, m_{s} = - \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = + 2, m_{s} = + \frac{1}{2}$

Identify the mismatch in the following pairs

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