Question

In the following question, if '+' stands for multiplication, '-' stands for division, '$\times$' stands for subtraction and '$÷$' stands for addition then
$\frac{(36\times 4)-8\times 4}{4+8\times 2+16÷1}$ = ?

• A. $0$
• B. $8$
• C. $12$
• D. $16$

Answer 1

The correct option is A $0$

$\frac{(36\times 4)-8\times 4}{4+8\times 2+16÷1}$
Replacing sign according to question. We get,
$\frac{(36-4)÷8-4}{4\times 8-2\times 16+1}\Rightarrow \frac{32÷8-4}{32-32+1}=\frac{4-4}{1}=0$
Hence, option $A$ is the correct answer.