Question

In the following question in every row the numbers outside the bracket are related to number inside the bracket in a specific manner. From the given alternative find the right number which matches and will replace the question mark.
$\begin{array}{ccc}52& \left(47\right)& 91\\ 26& \left(26\right)& 78\\ 65& (?)& 39\end{array}$

• A. $45$
• B. $82$
• C. $53$
• D. $34$

Answer 1

Answer: (C)

$53$

From the given table,

In the first row,

$52\times 7=364$ and $91\times 4=364$ i.e. $52\times y=364=91\times x$. So, $xy=47$ is the middle number.

In the $2^{nd}$ row,

$26\times 6=156$ and $78\times 2=156$

Similarly, $65\times y=65\times 3=195$ and $39\times x=39\times 5=195$

Hence, $53$ replaces question mark.