Question 13

In the following question out of the four options only one is correct, write the correct answer.

The digit in the ten's place of a two-digit number is 3 more than the digit in the unit's place. Let the digit at unit's place be b. Then, the number is:

(a)11b + 30

(b) 10b + 30

(c) 11b + 3

(d) 10b + 3

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Solution

Let digit at unit's place be b.
Then digit at ten's place =(b+3)
$∴$ Number=10(b+3)+b=10b+30+b=11b+30

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Similar questions

In the following question out of the four options only one is correct, write the correct answer.

The digit in the ten's place of a two-digit number is 3 more than the digit in the unit's place. Let the digit at unit's place be b. Then, the number is:

(a)11b + 30

(b) 10b + 30

(d) 10b + 3

Question 167

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