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Question

In the following question, three out of four alternatives contain alphabets placed in a particular form. Find the one that does not belong to the group.

A
MLONP
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B
HGJIK
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C
SRUTV
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D
WUYXZ
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Solution

The correct option is D WUYXZ
We have,
for option A,
M 1=L,
L +3=O,
O 1=N
and N +2=P
Similarly,
H 1=G,
G +3=J,
J 1=I
and I +2=K,
S 1=R,
R +3=U,
U 1=T
and T +2=V.

In WUXYZ, we have
W 2=U,
U +3=X,
X +1=Y
and Y +1=Z.
Therefore, WUXYZ is the odd one out as per the pattern.

Hence, option (D) is the correct answer.

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