In the following question, three out of four alternatives contain alphabets placed in a particular form. Find the one that does not belong to the group.
A
MLONP
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B
HGJIK
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C
SRUTV
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D
WUYXZ
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Solution
The correct option is D WUYXZ We have,
for option A,
M →−1=L,
L →+3=O,
O →−1=N
and N →+2=P Similarly, H →−1=G,
G →+3=J,
J →−1=I
and I →+2=K,
S →−1=R,
R →+3=U,
U →−1=T
and T →+2=V.
In WUXYZ, we have W →−2=U,
U →+3=X,
X →+1=Y
and Y →+1=Z. Therefore, WUXYZ is the odd one out as per the pattern.