Question

In the following question, two equations are given. Solve both the equations and mark the corresponding answer, if:

a) x is greater than y

b) x is less than y

c) x is greater than or equal than y

d) x is less than or equal to y

e) x = y or a definite relationship between x & y cannot be established

x${}^2$+ 9X + 20 = 0

Y${}^2$+ 5Y + 6 = 0

• A. (b)
• B. (c)
• C. (d)
• D. (e)

Answer 1

The correct option is A

(b)

x${}^2$ + 9x + 20 = 0

x${}^2$ + 4x + 5x + 20 = 0

[x + 4][x + 5] = 0

x = -4, -5

y${}^2$ + 5y + 6 = 0

y${}^2$ + 3y + 2y + 6 = 0

[y + 3][y + 2] = 0

y = -2, -3 x = -4, -5

So, clearly, x$<$ y