Question

In the following question, two equations are given. Solve both the equations and mark the corresponding answer, if:

a) x is greater than y

b) x is less than y

c) x is greater than or equal than y

d) x is less than or equal to y

e) x = y or a definite relationship between x & y cannot be established

2x${}^2$ + 3x + 1 = 0

12y${}^2$ + 7y + 1 = 0

• A. (a)
• B. (b)
• C. (c)
• D. (d)

Answer 1

The correct option is B

(b)

Here, x = -1 or - $\frac{1}{2}$

& y = - $\frac{1}{3}$ or - $\frac{1}{4}$

So, clearly x$<$ y