In the following question, two equations I and II are given. You have to solve both the equations and choose the appropriate answer.
I. 2a2+5a−3=0
II. 2b2−5b+3=0
if a < b
2a2+6a−a−3=0⇒(2a−1)(a+3)=0⇒a=±12,−3Also,2b2−2b−3b+3=0⇒(2b−3)(b−1)=0⇒b=32,1