Question

In the following question, two equations I and II are given. You have to solve both the equations and choose the appropriate answer.

I. 4a${}^2$ = 1

II. 4b${}^2$ - 12b + 5 = 0

• A. if a ≤ b
• B. if a ≥ b
• C. if a = b
• D. if a > b

Answer 1

The correct option is A

if a ≤ b

$\begin{array}{c}{a}^2=\frac{1}{4}\Rightarrow a=\pm \frac{1}{2}\\ Also,4b^2-10b-2b+5=0\Rightarrow \left(2b-1\right)\left(2b-5\right)=0\Rightarrow b=\frac{1}{2},\frac{5}{2}\end{array}$