In the following question, two equations numbered I and II are given. Find the values for x and y and choose the appropriate answer.

$I . 225 x^{2} - 4 = 0 I I . \sqrt{225 y} + 2 = 0$

if x > y

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y > x

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x ≤ y

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y ≤ x

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x = y or the relationship cannot be established

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Solution

The correct option is E
x = y or the relationship cannot be established

$I . 225 x^{2} = 4 \Rightarrow x^{2} = \frac{4}{225} \Rightarrow x = \pm \frac{2}{15} I I . \sqrt{225 y} + 2 = 0 \Rightarrow \sqrt{225 y} = - 2 S q u a r i n g o n b o t h s i d e s, 225 y = 4 \Rightarrow y = \frac{4}{225}$

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In the following question, two equations numbered I and II are given. Find the values for x and y and choose the appropriate answer. I.225x2−4=0II.√225y+2=0

The correct option is E x = y or the relationship cannot be established I. 225x2=4⇒x2=4225⇒x=±215II.√225y+2=0⇒√225y=−2Squaring on both sides, 225y=4⇒y=4225

In the following question, two equations numbered I and II are given. Find the values for x and y and choose the appropriate answer.

$I . 225 x^{2} - 4 = 0 I I . \sqrt{225 y} + 2 = 0$

The correct option is E
x = y or the relationship cannot be established

$I . 225 x^{2} = 4 \Rightarrow x^{2} = \frac{4}{225} \Rightarrow x = \pm \frac{2}{15} I I . \sqrt{225 y} + 2 = 0 \Rightarrow \sqrt{225 y} = - 2 S q u a r i n g o n b o t h s i d e s, 225 y = 4 \Rightarrow y = \frac{4}{225}$