In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
$I . 6 x^{2} + 7 x + 2 = 0$
$I I . y^{2} - y - 2 = 0$

x > y

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x < y

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x = y or the relationship between 'x' & 'y' cannot be determined

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Solution

The correct option is E x = y or the relationship between 'x' & 'y' cannot be determined
$6 x^{2} + 7 x + 2 = 0 (3 x + 2) (2 x + 1) = 0 x = - \frac{2}{3} o r - \frac{1}{2} y^{2} - y - 2 = 0 (y - 2) (y + 1) = 0 y = - 1 o r + 2 I f x = - \frac{1}{2}, y = - 1, t h e n x > y I f x = - \frac{1}{2}, y = + 2, t h e n x < y$
So, a definite relationship between x and y cannot be established.

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