In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

I. $4 x^{2} - 41 x + 105 = 0$
II. $20 y^{2} + 101 y - 21 = 0$

if x > y

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if x < y

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if x

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if x

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if x = y or relationship between x and y cannot be determined

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Solution

The correct option is A if x > y
$4 x^{2} - 41 x + 105 = 0$
$\Rightarrow (4 x - 21) (x - 5) = 0$
$\Rightarrow x = \frac{21}{4}, 5$
$20 y^{2} + 101 y - 21 = 0$
$\Rightarrow (4 y + 21) (5 y - 1) = 0$
$\Rightarrow (4 y + 21) (5 y - 1) = 0$
$\Rightarrow y = - \frac{21}{4}, \frac{1}{5}$
$∴ x > y$

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In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option: I. 4x2−41x+105=0 II. 20y2+101y−21=0

The correct option is A if x > y4x2−41x+105=0 ⇒(4x−21)(x−5)=0 ⇒x=214,5 20y2+101y−21=0 ⇒(4y+21)(5y−1)=0 ⇒(4y+21)(5y−1)=0 ⇒y=−214,15 ∴x>y

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

I. $4 x^{2} - 41 x + 105 = 0$
II. $20 y^{2} + 101 y - 21 = 0$

The correct option is A if x > y
$4 x^{2} - 41 x + 105 = 0$
$\Rightarrow (4 x - 21) (x - 5) = 0$
$\Rightarrow x = \frac{21}{4}, 5$
$20 y^{2} + 101 y - 21 = 0$
$\Rightarrow (4 y + 21) (5 y - 1) = 0$
$\Rightarrow (4 y + 21) (5 y - 1) = 0$
$\Rightarrow y = - \frac{21}{4}, \frac{1}{5}$
$∴ x > y$