In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
$I . 2 x^{2} + 2 x - 60 = 0$
$I I . 2 y^{2} - 5 y + 3 = 0$

if x > y

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if x < y

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if x

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if x

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if x = y or relationship between x and y cannot be determined

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Solution

The correct option is E if x = y or relationship between x and y cannot be determined
$2 x^{2} + 2 x - 60 = 0 (2 x - 10) (x + 6) = 0 \Rightarrow x = 5, - 6. 2 y^{2} - 5 y + 3 = 0 (2 y - 3) (y - 1) = 0 \Rightarrow y = \frac{3}{2}, 1$
$∴$ The relationship between x and y cannot be established.

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In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option: I. 2x2+2x−60=0 II. 2y2−5y+3=0

The correct option is E if x = y or relationship between x and y cannot be determined2x2+2x−60=0(2x−10)(x+6)=0⇒x=5,−6.2y2−5y+3=0(2y−3)(y−1)=0⇒y=32,1 ∴ The relationship between x and y cannot be established.

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
$I . 2 x^{2} + 2 x - 60 = 0$
$I I . 2 y^{2} - 5 y + 3 = 0$

The correct option is E if x = y or relationship between x and y cannot be determined
$2 x^{2} + 2 x - 60 = 0 (2 x - 10) (x + 6) = 0 \Rightarrow x = 5, - 6. 2 y^{2} - 5 y + 3 = 0 (2 y - 3) (y - 1) = 0 \Rightarrow y = \frac{3}{2}, 1$
$∴$ The relationship between x and y cannot be established.