In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
I. $x^{2} + 4 x + 4 = 0$
II. $y^{2} - 8 y + 16 = 0$

if x

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if x > y

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if x

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if x < y

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if x = y, or no definite relationship can be established between x and y

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Solution

The correct option is D if x < y
$I . x^{2} + 4 x + 4 = 0 (x + 2)^{2} = 0 ∴ x = - 2$

$I I . y^{2} - 8 y + 16 = 0 \Rightarrow (y - 4)^{2} = 0 ∴ y = 4$

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In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option: I. x2+4x+4=0 II. y2−8y+16=0

The correct option is D if x < yI. x2+4x+4=0(x+2)2=0∴ x=−2 II.y2−8y+16=0⇒(y−4)2=0∴ y=4

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:
I. $x^{2} + 4 x + 4 = 0$
II. $y^{2} - 8 y + 16 = 0$

The correct option is D if x < y
$I . x^{2} + 4 x + 4 = 0 (x + 2)^{2} = 0 ∴ x = - 2$

$I I . y^{2} - 8 y + 16 = 0 \Rightarrow (y - 4)^{2} = 0 ∴ y = 4$