In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

$I . (x + 3) (y + 2) = 12$
$I I . 2 x y + 4 x + 5 y = 11$

if x > y

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if x < y

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if x ≥ y

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if x ≤ y

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if x = y or definite relationship cannot be established between ‘x’ and ‘y’

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Solution

The correct option is A if x > y
$I . x y + 2 x + 3 y + 6 = 12 \to 2 x y + 4 x + 6 y = 12 I I . 2 x y + 4 x + 5 y = 11$
Subtracting (ii) from (i), we get
$∴ y = 1$
Putting the value of y in (i), we get
$∴ x = 3$
Hence, $x > y$

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In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option: I.(x+3)(y+2)=12 II.2xy+4x+5y=11

The correct option is A if x > yI. xy+2x+3y+6 = 12→ 2xy+4x+6y = 12II. 2xy+4x+5y = 11 Subtracting (ii) from (i), we get ∴ y=1 Putting the value of y in (i), we get ∴ x=3 Hence,x>y

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

$I . (x + 3) (y + 2) = 12$
$I I . 2 x y + 4 x + 5 y = 11$

The correct option is A if x > y
$I . x y + 2 x + 3 y + 6 = 12 \to 2 x y + 4 x + 6 y = 12 I I . 2 x y + 4 x + 5 y = 11$
Subtracting (ii) from (i), we get
$∴ y = 1$
Putting the value of y in (i), we get
$∴ x = 3$
Hence, $x > y$