In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

$I . x - 7 = 0$
$I I . 3 y^{2} - 10 y + 7 = 0$

x = y

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x > y

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x < y

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Solution

The correct option is B x > y
From I, $x - 7 = 0 x = 7 \dots (1)$
From II, $3 y^{2} - 10 y + 7 = 0 3 y^{2} - 3 y - 7 y + 7 = 0 (3 y - 7) (y - 1) = 0 y = 1 o r y = \frac{7}{3} \dots (2)$
From (1) and (2), we have $x > y$

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In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option: I. x−7 = 0 II. 3y2−10y+7 = 0

The correct option is B x > yFrom I, x−7=0x=7⋯(1) From II, 3y2−10y+7=03y2−3y−7y+7=0(3y−7)(y−1)=0y=1 or y=73⋯(2) From (1) and (2), we have x>y

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

$I . x - 7 = 0$
$I I . 3 y^{2} - 10 y + 7 = 0$

The correct option is B x > y
From I, $x - 7 = 0 x = 7 \dots (1)$
From II, $3 y^{2} - 10 y + 7 = 0 3 y^{2} - 3 y - 7 y + 7 = 0 (3 y - 7) (y - 1) = 0 y = 1 o r y = \frac{7}{3} \dots (2)$
From (1) and (2), we have $x > y$