Question

In the following question, two equations numbered I and II are given. Solve both the equations and mark the appropriate option:

I. $32x^2-68x+35=0$
II. $y^2+10y+24=0$

• A. if x > y
• B. if x < y
• C. if xy
• D. if xy
• E. if x = y or relationship between x and y cannot be determined

Answer 1

Answer: (A)

if x > y

$32x^2-68x+35=0\Rightarrow (4x-5)(8x-7)=0\Rightarrow x=\frac{5}{4},\frac{7}{8}\Rightarrow y^2+10y+24=0\Rightarrow (y+4)(y+6)=0\Rightarrow y=-4,-6\therefore x>y$