In the following questions, a letter series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternative. Find the correct alternative.
$B A . . . . B . . . . . A A B . . . . . A . . . . . B$

A A B B

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B A B B

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B A A B

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A B B A

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A B A A

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Solution

The correct option is A $A B B A$
One character per blank.
Simple repeating unit of 4.
Check the last and the first part of the series. The unit will be $B A . . . B$
Compare with the series. We find, repeating unit is $B A A B$
Just compare the blanks.

Answer is $A B B A$ , that is $(D)$

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