Question

In the following questions, a letter series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternative. Find the correct alternative.

$C....CCD....CCDC.....CC.....BC$

• A. $DBCD$
• B. $DBDD$
• C. $BDAA$
• D. $BDCD$
• E. $DCBD$

Answer 1

Answer: (A)

$DBCD$

Observe series carefully. We see that we can't solve this by considering repeating units. Instead we need to find a pattern to solve the series.

We can conclude:

$\left(1\right)$ $B$ here acts as a 'series stopper'.

$\left(2\right)$ The no. of $C$s before every $D$ multiplies by 2.

$\left(3\right)$ After $B$, the no. of consecutive $C$s also increase by one.

We see that the series must be like this:

$CDCCDBCCDCCCCDBC$

At first, $1$ C before D. Then $1\times 2$ C before D.

After B, $1+1$ C before D. The $2\times 2$ C before D.

Get answer $DBCD$ that is $\left(A\right)$