Question

In the following questions two equations I and II are given. You have to solve both the equations and give answer.

$I.2a+3b=31$

$II.3a-2b=1$

• A. if a < b
• B. if a ≤ b
• C. if a ≥ b
• D. if a = b
• E. if a > b

Answer 1

The correct option is A

if a < b

2a + 3b = 31...(i)
3a - 2b = 1...(ii)
Multiply (i) by 2 and (ii) by 3 then adding (i) and (ii), we get $a=\frac{65}{13}=5$
Putting the value of `a' in any equation, we get b = 7.
Hence $b>$a or $a<b$