Question

In the following questions two equations I and II are given. You have to solve both the equations and choose the appropriate answer.

I. 6a${}^2$ + 5a + 1 = 0

II. 15b${}^2$ + 19b + 6b = 0

• A. if a ≤ b
• B. if a ≥ b
• C. if a = b
• D. if a > b

Answer 1

The correct option is D

if a > b

$\begin{array}{c}6a^2+2a+3a+1=0\Rightarrow \left(2a+1\right)\left(3a+1\right)=0\therefore a=\frac{-1}{3},\frac{-1}{2}Also,15b^2+10b+9b+6=0\left(5b+3\right)\left(3b+2\right)=0b=-\frac{3}{5},\frac{-2}{3}\end{array}$