Question

In the following questions, two equations numbered I and II are given. You have to solve both equations and answer as: (RBI GRADE-B)
I. x${}^2$ + 6x - 16 =0
II. y${}^2$ - 6y+5=0

• A.
  x > y
• B.
  x < y
• C. x $\ge$ y
• D.
  x $\le$ y
• E.
  x = y or relation cannot be established.

Answer 1

The correct option is C x $\ge$ y

x = y or relation cannot be established
$x=\frac{[-6\pm \sqrt{6^2-(4times1\times -16)}]}{2\times 1}=-3\pm 5=2-8or2$
$x=\frac{[6\pm \sqrt{(-6{)}^2-(4times1\times -5)}]}{2\times 1}=-3\pm 2=1or5$
Least value of y = 1 < 2 = Largest value of x