Question

In the following questions, two equations numbered I and II are given. You have to solve both equations and answer as: (RBI GRADE-B)
I. x${}^2$ - 11x + 28 = 0
II. y${}^2$ - 14y + 48 = 0

• A.
  x > y
• B.
  x < y
• C.
  x $\ge$ y
• D.
  x $\le$ y
• E. x = y or relation cannot be established.

Answer 1

The correct option is E x = y or relation cannot be established.

x${}^2$ - 11x + 28 =0
x = 7, 4
y${}^2$ - 14y + 48 = 0
y = 6, 8
So, a relationship cannot be established.