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Introduction

In the follow...

Question

In the following reaction:
$2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)$ the equilibrium is not attained. The rate of forward reaction is greater than that of backward reaction. Thus, which of the following is the correct relation between $K_{p}$ and $Q_{p}$ ?

K_{p} = Q_{p}

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Q_{p} > K_{p}

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Q_{p} < K_{p}

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K_{p} = Q_{p} = 1

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Solution

The correct option is C $Q_{p} < K_{p}$
When
$Q_{c} = K_{c}$ reaction is at equilibrium,
When Q > K, the reaction proceeds in backward direction.
When Q < K, the reaction proceeds in forward direction.

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