In the following reaction 'A' is

C_{2} H_{3} {C H}_{2} C H O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{2} H_{5} {C H}_{2} O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{3} {C H}_{2} O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{3} C H O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C_{2} H_{3} {C H}_{2} C H O$
The reaction of grignard Reagent plus Epoxide, it produce primary alcohol. The reaction followed $S N^{2}$ mechanism.

Suggest Corrections

Similar questions

I U P A C

C H C I = C H C I

C_{2} H_{5} CC H_{3} = CC H_{3} C_{2} H_{5}

C H_{3} C H_{2} C H_{2} CHO, C H_{3} C H_{2} C H_{2} CH_{2} OH, C_{2} H_{5} O C_{2} H_{5}, C H_{3} C H_{2} C H_{2} C H_{3}

S - S

C_{2} H_{5} - S - C_{2} H_{5}; Δ H_{f}^{o} = - 147 k J {m o l}^{- 1}

C_{2} H_{5} - S - S - C_{2} H_{5}; Δ H_{f}^{o} = - 201.9 k J {m o l}^{- 1}

S (g) - Δ H_{f}^{o} = - 222.8 k J {m o l}^{- 1}

{C H}_{3} - O - C_{2} H_{5} H_{2} {S O}_{4}, H_{2} O - ------ \to c o n c

C_{2} H_{5} C \equiv C H C H_{3} M g B r - ------------- \to A 1. H C H O ⟶ 2. H_{3} O^{+} B

Join BYJU'S Learning Program