In the following reaction between lead sulphide and hydrogen peroxide-PbS -160-s- -160- -160- -160- -160-4H2O2 -160-aq- -160- -160- -8594- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160-PbSO4 -160-s- -160- -160- -160- -160-4H2O -160-1-a- which substance is reduced-b- Which substance is oxidised-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Redox Reaction

In the follow...

Question

In the following reaction between lead sulphide and hydrogen peroxide:
$PbS (s) + 4 H_{2} O_{2} (aq) \underset{}{\to} {PbSO}_{4} (s) + 4 H_{2} O (1)$
(a) which substance is reduced?
(b) Which substance is oxidised?

Open in App

Solution

Suggest Corrections

Similar questions

PbS (s) + 4 H_{2} O_{2} (aq) \underset{}{\to} {PbSO}_{4} (s) + 4 H_{2} O (1)

P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O

H_{2} S + 2 F e C l_{3} \to 2 F e C l_{2} + 2 H C l + S

2 A g B r (s) + C_{6} H_{6} O_{2} (a q) \to 2 A g (s) + 2 H B r (a q) + C_{6} H_{4} O_{2} (a q)

In the reaction, H₂S + Cl₂ → 2HCl + S; hydrogen sulphide is:

Join BYJU'S Learning Program