In the following reaction,
$C H_{3} \begin{matrix} O ∥ \end{matrix} C O H + C H_{3} C H_{2} 18 O H ⟶ C H_{3} \begin{matrix} O ∥ \end{matrix} C O C_{2} H_{5} + H_{2} O$
molar mass difference between water formed in the reaction and ordinary water is X unit. Find out the value of X.

X = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

X = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X = 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $X = 0$
In esterification reaction, the OH from acid and H from alcohol is removed as water.

This means the isotopically labelled oxygen becomes part of ethyl acetate. It is not a part of water.

In the given reaction, the molar mass difference between water formed in the reaction and ordinary water is 0 unit.

Option A is correct.

Suggest Corrections

Similar questions

Arrange in decreasing order of basicity,

$H_{2} O, O H^{-}, C H_{3} O H, C H_{3} O^{-}$

Identify X in the following reaction
X + Water $\to$ Base.

\to

H_{2} S O_{4}^{-} + H_{2} O \to H_{2} S O_{4} + O H^{-} X

Join BYJU'S Learning Program