In the following reaction H 2 O 2 act as H 2 O 2- X - O 2- BA- OxidantB- CatalystC- ReductantD- Dehydrating agent

The correct option is C Reductant Oxidation state of Oxygen changed from 1 to 0 ...

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Nomenclature of Coordination Compounds

In the follow...

Question

In the following reaction $H_{2}$ $O_{2}$ act as

$H_{2}$ $O_{2}$ + X $\to$ $O_{2}$ + B

Oxidant

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Catalyst

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Dehydrating agent

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Reductant

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Solution

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Similar questions

In the following reaction $H_{2}$ $O_{2}$ act as

$H_{2}$ $O_{2}$ + X $\to$ $O_{2}$ + B

H_{2} O_{2}

(a)

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

(b)

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

(c)

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

(d)

H_{2} O_{2} + 2 O H^{-} - 2 e^{-} \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2} + 2 H^{\oplus} + 2 e^{⊖} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{⊖} \to O_{2} + 2 H^{\oplus}

H_{2} O_{2} + 2 e^{⊖} \to 2 O H^{⊖}

H_{2} O_{2} + 2 O H^{⊖} - 2 e^{⊖} \to 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2} + 2 H^{\oplus} + 2 e^{⊖} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{⊖} \to O_{2} + 2 H^{\oplus}

H_{2} O_{2} + 2 e^{⊖} \to 2 O H^{⊖}

H_{2} O_{2} + 2 O H^{⊖} - 2 e^{⊖} \to 2 H_{2} O

H_{2} O_{2}

A g_{2} O + H_{2} O_{2} \to 2 A g + H_{2} O + O_{2}

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