Question

In the following reaction, hydrazine is oxidised to $N_2$.
$N_2{H}_4+O{H}^{-}\to N_2+H_{2}O+e^{-}$.
The equivalent mass of $N_2{H}_4$(hydrazine) is:

• A. 8
• B. 16
• C. 32
• D. 64

Answer 1

Answer: (A)

8

In the reaction

$N_2{H}_4+{OH}^{-}⟶N_2+H_{2}O+e^{-}$

in $N_2{H}_4$ Oxidation state of Nitrogen is $+2$

in ${ N }_{ 2 }$ Oxidation state of Nitrogen is O.

Now, as 2 atoms of $N$ in $N_2{H}_4$ is converting from +2 to 0.

So $nf=4$

$EquivalentMass=\frac{Molecularmass}{nf}$

$EquivalentMass=\frac{32}{4}=8$