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Question

In the following reaction, identify the species oxidised, the species reduced, the oxidising agent and the reducing agent.
4HCl+MnO2MnCl2+2H2O+Cl2.

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Solution

MnO2+4HCl=MnCl2+Cl2+2H2O
Writing the oxidation numbers on various atoms,
+4Mn2O2++14H1Cl=+2Mn1Cl2+0Cl2++12H22O
Ox.no. of Mn changes from +4 to +2, i.e., decrease in oxidation number. MnO2 is thus reduced. It acts as an oxidising agent. Ox. no. of Cl changes from 1 to 0, i.e., increase in oxidation number. HCl is thus oxidised. It acts as a reducing agent.

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