In the following reaction, identify the substance, ‘X’ from the given options.
$F e + C u S O_{4} \to X + C u$

F e S O_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Fe-Cu

No worries! We‘ve got your back. Try BYJU‘S free classes today!

FeS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

CuS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $F e S O_{4}$
In a reaction between a metal and the salt solution of another metal, the more reactive metals can displace less reactive metals from their compounds in solution or molten form. In the above reaction, iron (Fe) metal is more reactive than copper (Cu) metal. So, Fe displaces Cu from $C u S O_{4}$ solution and forms $F e S O_{4}$ .

Suggest Corrections

Similar questions

In the following reaction, identify the substance, ‘X’ from the given options.
$F e + C u S O_{4} \to X + C u$

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

In the following reaction, identify the products X and Y.
$C u + F e S O_{4} \to X + Y$

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

F e + 2 H C l \to F e C l_{2} + H_{2}

F e S + 2 H C l \to F e C l_{2} + H_{2} S

F e + S Δ - \to F e S

N a C l + H_{2} S O_{4} < 200^{o} C - --- \to N a H S O_{4} + H C l

C u S O_{4} + H_{2} S \to C u S + H_{2} S O_{4}

S + H_{2} S O_{4} \to 3 S O_{2} + H_{2} O

Join BYJU'S Learning Program