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Enthalpy

In the follow...

Question

In the following reaction,

$M n O_{2} + 4 H C l \to {M n C l}_{2} + {C l}_{2} + 2 H_{2} O$ , n-factor of HCl is:

A

1 / 2

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B

1

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C

2

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D

4

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Solution

The correct option is B $1 / 2$
4 Moles of HCl loses 2 moles of electron in the given reaction , So n-facor of HCL is $\frac{1}{2}$

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Similar questions

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

1

H C l

1

M n O_{2}

is heated together, the maximum weight of

C l_{2}

gas evolved will be:

Q. Assertion :One equivalent of

M n O_{2}

reacts with 2 equivalents of

H C l

in the reaction,

M n O_{2} + 4 H C l ⟶ M n C l_{2} + 2 H_{2} O + C l_{2}

. Reason: One equivalent of

M n O_{2}

reacts with one equivalent of

H C l

.

1

H C l

1

M n O_{2}

are heated together, the maximum weight of

C l_{2}

gas evolved will be :

M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

0.80

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146

H C l

react in the following manner:

M n O_{2} + 4 H C l ⟶ M n C l_{2} + C l_{2} + 2 H_{2} O

Q. The substance that is oxidised in the following chemical reaction is:

M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}

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