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Question


In the following reaction, \( R _{2} CuLi \stackrel{ RX }{\longrightarrow} R - R ^{\prime}+ RCu + LiX \text {, the nature of } R \text { and } R ^{\prime} \text { should be } \)

A

Any alkyl and 20 Alkyl

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B

R= any alkyl; R1=Methyl or alkyl or 20 cycloalkyl

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C

R=10 alkyl; R1 = any alkyl

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D

R= any alkyl ; R1= any alkyl

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Solution

The correct option is B

R= any alkyl; R1=Methyl or alkyl or 20 cycloalkyl


The given reaction is Corey - house synthesis. An alkyl halides is first treated with Li metal in Dry ether to form alkyl lithium. This upon reaction with Cuprous iodide yields Lithium dialkyl cuprate.

RXLi−−−−dry etherRLi+LiX

2RLi+CulLi(R)2Cu+Lil (Lithium dialkyl cuprate)

Lithium dialkyl cuprate is known as Gilman reagent

RX+R2LiCuDry−−etherRR+RCu+LiX

Foe Better yields,

R = any alkyl

R'= Methyl or Primary alkyl or secondary alkyl or secondary cycloalkyl or vinyl or aryl

In other words , R'X should not be a tertiary alkyl halide.


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