Question

In the following reaction sequence, the products B and C so formed, both give same product $(\pm )$ epichlorohydrin, when reacted with base NaOH.


Products B and C are positional isomers.
Select the true option(s) from the following about epichlorohydrin.

• A. It is a halohydrin
• B. It is an epoxide
• C. $C{H}_{3}C{H}_2{O}^{-}$ attacks on carbon attached to $Cl$ to give
• D. $C{H}_{3}C{H}_2{O}^{-}$ attacks on less hindered carbon attached to $O$ to give

Answer 1

Answer: (B), (D)

$C{H}_{3}C{H}_2{O}^{-}$ attacks on less hindered carbon attached to $O$ to give

The product A formed by radical chain mechanism.

Explanation:
(a) Halohydrin is $\beta -haloalcohol$, so it is not halohydrin.
(b) It is an epoxide.
(c) $C{H}_{3}C{H}_2{O}^{-}$ attacks on less hindered carbon attached to $O$ to give compound in option (d).