In the following reaction- SO 2 acts as a reducing agent SO 2- Cl 2-2 H 2 O - H 2 SO 4-2 HCl- The equivalent weight of SO 2 will beA- 64B- 32C- 16D- 8

The correct option is B 32 Equivalent weight = Molecular weight/Total change in oxidation number S changes oxidation state from + 4 to +6 ...

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Valency and Oxidation State

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Question

In the following reaction, $S O_{2}$ acts as a reducing agent $S O_{2} + C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l$ . The equivalent weight of $S O_{2}$ will be

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S O_{2}

S O_{2} + C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l

S O_{2}

S O_{2}

S O_{2} + C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l

S O_{2}

S O_{2} + C l_{2} + 2 H_{2} O \to 2 H C l + H_{2} S O_{4}

S O_{2} + 2 H_{2} S \to 3 S + 2 H_{2} O

2 A g + 2 H_{2} S O_{4} \to {A g}_{2} S O_{4} + 2 H_{2} O + S O_{2}

H_{2} S O_{4}

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