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Stereoisomerism

In the follow...

Question

In the following reaction started only with $A_{8}, 2 A_{8} (g) ⇌ 3 A_{2} (g) + 3 A_{2} (g) + A_{4} (g)$ mole fraction of $A_{2}$ is found to $0.36$ at a total pressure of $100 a t m$ at equilibrium. The mole fraction of $A_{8} (g)$ at equilibrium is:

A

0.28

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B

0.72

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C

0.18

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D

None of these

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Solution

The correct option is A $0.28$
$\begin{matrix} 2 A_{8} & ⇌ & 2 A_{3} & + & 3 A_{2} & + & A_{4} t = 0 & 2 & 0 & 0 & 0 t = t_{e q} & 2 - 2 α & 2 α & 3 α & α \end{matrix}$
$n_{T} = 2 + 4 α$
Given mole fraction of $A_{2}$ is $0.36$
$0.36 = \frac{3 α}{2 + 4 α}$
$α = 0.46$
Mole fraction of $A_{8}$
$X_{A_{8}} = \frac{2 - 2 α}{2 + 4 α} = \frac{2 - 2 \times 0.46}{2 + 4 \times 0.46} = 0.28$

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Stereoisomerism

Standard XII Chemistry

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