In the following reaction, the alkene affords the compound 'B'
$C H_{3} C H = C H C H_{3} + O_{3} Z n - - \to H_{2} O B$
The compound B is:

C H_{3} C O C H_{3}

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C H_{3} C H_{2} C O C H_{3}

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C H_{3} C H O

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C H_{3} C H_{2} C H O

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Solution

The correct option is C $C H_{3} C H O$
Ozonolysis of alkenes involves the addition of an ozone molecule to an alkene, to form an ozonide. Formed ozonide undergoes cleavage by $Z n / H_{2} O$ to give smaller oxidised product. Here product B is acetaldehyde.
$C H_{3} C H = C H C H_{3} + O_{3} Z n - - \to H_{2} O 2 C H_{3} C H O$

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Similar questions

C H_{3} C H = C H C H_{3} O_{3} - \to A H_{2} O - - \to Z n B

B

C H_{3} C H = C H C H_{3} O_{3} - \to A Z n / H_{2} O - ---- \to B

B r_{2}

C H_{2} C l_{2}

D

C H_{3} - C H (C H_{3}) - C H_{2} - C H_{2} - B r a l c . K O H - ----- \to Δ A (i) C o n c . H_{2} S O_{4} - --------- \to (i i) H_{2} O / Δ B Major product + C Minor product

B H I / Δ - --- \to - H_{2} O D Major product + E Minor product

C H_{3} - C H (C H_{3}) - C H (C H_{3}) - C H_{2} - C H_{3}

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